## [PlaidCTF 2019] Project Eulernt

Guys, guys, don’t fight. I’m sure we’ll be able to come up with something roughly equal. source eulernt.pwni.ng:5555 NOTE: We originally uploaded the wrong version. It is still available here if you really want it: wrong version. How to solve We need to get a divisor of $333!$ that is close to $(333!)^{1/2}$. Just factorize with factorDB. There are some $p^k$s of which $k$ is odd. Let’s define a product of those $p$s as $v := \prod p$....